Ex 25, 9 Verify (i) x3 y3 = (x y) (x2 – xy y2) LHS x3 y3 We know (x y)3 = x3 y3 3xy (x y) So, x3 y3 = (x y)3 – 3xy (x y) = (x y)3 – 3xy (x y) = (x y) (x y)2 – 3xy) Using (ab)2 = a2 b2 2ab = (x y) (x2 y2 2xy) – 3xy = (x y) (x2 y2 – xy) = (x y) (x2 xy y2) = RHS RHS (x y) (x2 – xy y2) Hence proved(xyz)^3 (x y z)(x y z)(x y z) We multiply using the FOIL Method x * x = x^2 x * y = xy x * z = xz y * x = xy y * y = y^2 y * z = yz z * x = xz z * y = yz z * z = z^2 x^3 y^3 z^3 3x^2y 3xy^2 3x^2z 3z^2x 3y^2z 3z^2y 6xyz Lennox Obuong Algebra Student Question How do I plot the equation x^3 y^3 3xy=0 s are words are used to describe and categorize your content Combine multiple words with dashes(),
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(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)
(x-y)^(3)=x^(3)-y^(3)-3xy(x-y) =x^(3)-3x^(2)y+3xy^(2)-y^(3)-So we set it = 0 i*sqrt(3)(x1) = 0 x1 = 0 x = 1 Then substituting that y = y = y = y = 1 So we end up with all solutions {(x,y) x y = 1} plus the one solution (x,y) = (1,1) Now if you were asking about xy instead of xy, the answer would be xy is always either 1 or 2 Are you sure you didn't make a typo and you were asking about xy and not xy? Explanation differentiate implicitly with respect to x The product rule has to be used on the right side 3x2 3y2 dy dx = 3x dy dx 3y ⇒ 3y2 dy dx −3x dy dx = 3y − 3x2 ⇒ dy dx (3y2 −3x) = 3(y − x2) ⇒ dy dx = 3(y − x2) 3(y2 − x) = y − x2 y2 − x Answer link
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#(xy)^3=(xy)(xy)(xy)# Expand the first two brackets #(xy)(xy)=x^2xyxyy^2# #rArr x^2y^22xy# Multiply the result by the last two brackets #(x^2y^22xy)(xy)=x^3x^2yxy^2y^32x^2y2xy^2# #rArr x^3y^33x^2y3xy^2# Tính giá trị của biểu thức P=x^3y^33xy biết xy=1 Cho xy=1 Tính giá trị của a) P = x3 y3 3xy P = x 3 y 3 3 x y b) Q = x3 y3 3xy(x2 y2) 6x2y2 (x y) Q = x 3 y 3 3 x y ( x 2 y 2) 6 x 2 y 2 ( x y) Theo dõi Vi phạm Toán 8 Bài 3 Trắc nghiệm Toán 8 Bài 3 Giải bài tập Toán 8 Bài 3SOLUTION 15 Since the equation x 2 xy y 2 = 3 represents an ellipse, the largest and smallest values of y will occur at the highest and lowest points of the ellipse This is where tangent lines to the graph are horizontal, ie, where the first derivative y'=0
Locus of all point $P(x,y)$ satisfying $x^3y^33xy=1$ consists of union of $(A)$a line and an isolated point $(B)$a line pair and an isolated pointPiece of cake Unlock StepbyStep Natural Language Stepbystep explanation we know that A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or In this problem we have therefore The constant of proportionality is k=3 quarterfreelp and 26 more users found this answer helpful heart outlined Thanks 11
2 92k views Find the maximum and minimum values of x 3 3 x y 2 − 3 x 2 − 3 y 2 4 written 55 years ago by shailymishra30 ♦ 480 • modified 55 years ago Mumbai University > First Year Engineering > Sem 1 > Applied Maths 1 Marks 6 MTranscribed image text Find all the partial derivatives of the first and the second order for f(x, y) = x^2 3xy^2 2y 5 1) Find fx, fy and fxy for e^2x sin (Piy/3) 3) Find fx , fy , and for x^2 y e^xy^4 5) Find fx (x, y) and fy(x, y) for f(x, Y) = xy/x^2y^2 5) Find an equation of the tangent plane to the surface z = 8? If u = x^3 3xy^2 y^3 then ∂^2u/∂y∂x is (a) 3 (b) 6y (c) 6x (d) 2 asked in Applications of Differentiation by Darshee ( 493k points) applications of differentiation
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Click here👆to get an answer to your question ️ If x^3 y^3 = 3axy , find dydx Solve Study Textbooks Join / Login Question If x 3 y 3 = 3 a x y, find d x d y Thay $1=(xy)^3$ vào biểu thức A ta có A=$\frac{(xy)^3}{x^3y^3}\frac{(xy)^3}{xy}=\frac{x^3y^33xy(xy)}{x^3y^3}\frac{x^3y^33xy(xy)}{xy}=1\frac{3xy Find the extreme values of the function x 3 y 3 – 3xy differential calculus;
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F(x)=x³y³3xy f'x=3x²3y=0, 得y=x² f'y=3y²3x=0，代入y得：x^4x=0, 得x=0, 1 得驻点(0, 0) (1, 1) A=f"xx=6x B=f"xy=3 C=f"yy=6y 在(0, 0), A=C=0, B²AC=9>0, 所以这不是极值点；X^3y^3=3xy WolframAlpha Volume of a cylinder?Elaborating x 3 y 3 using identity a 3 b 3 = (a b)(a 2 ab b 2) = x ( x y)(x 2 xy y 2) 3xy (x y ) Taking common x( x y ) in both the terms = x ( x y){x 2 xy y 2 3y} ∴ x (x 3 y 3) 3xy ( x y) = x ( x y )(x 2 xy y 2 3y)
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D) 3 x y Solution The answer is D Using identity, (a b) 2 = a 2 b 2 2 a b) = (x y) (3 x y) Hence, one of the factor of given polynomial is 3xy Suggest CorrectionsY^2 at the point a) ( 2, 1, 3), b) ( 0, 1, 7), c) ( 1, ?Factor out the Greatest Common Factor (GCF), '3xy' 3xy(y x) = 0 Ignore the factor 3 Subproblem 1 Set the factor 'xy' equal to zero and attempt to solve Simplifying xy = 0 Solving xy = 0 Move all terms containing x to the left, all other terms to the right Simplifying xy = 0 The solution to this equation could not be determined
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Share It On Facebook Twitter Email 1 Answer 1 vote answered by Taniska (645k points) selected by Vikash Kumar Best answer Let f (x, y) = x 3 y 3 – 3xy Which of the following is a factor of (x y) 3 – (x 3 y 3 )?Consider the function f(x;y) = 3 p x2y Show that the directional derivative exists at the origin (by letting ~u= hcos( );sin( )iand using the de nition), BUT, fis not di erentiable at the origin (because if it were, we could use rf~uto compute D ~uf) SOLUTION Compute the directional derivative at the origin by using the de nition D uf(0;0
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Ex 25, 13 If x y z = 0, show that x3 y3 z3 = 3xyz We know that x3 y3 z3 3xyz = (x y z) (x2 y2 z2 xy yz zx) Putting x y z = 0, x3 y3 z3 3xyz = (0) (x2 y2 z2 xy yz zx) x3 y3 z3 3xyz = 0 x3 y3 z3 = 3xyz Hence proFactor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)SOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sides
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User Simplify 2(x y) 3(x y)2xy 3xy 5xy 5x 5y Weegy 2(x y) 3(x y) 2x 2y 3x 3y = 5x 5y paralPoints User Simplify 15 6(x 1)6x 15 6x 21 6x 16 User Simplify 5(MN 1) 55MN 5MN 4 5MN 4 Weegy 5(MN 1) 5 = 5MN 5MN 5 5 = 5MN User Simplify 8(xy 8) 18xy 9 8xy 65 8xy 73Differential equation Solve ( 2 x y 4 e y 2 x y 3 y) d x ( x 2 y 4 e y − x 2 y 2 − 3 x) d y = 0 written 55 years ago by aksh_31 ♦ 25k • modified 55 years ago Mumbai University > First Year Engineering > sem 2 > Applied Maths 2 Marks 6 Year 13U = x log xy x 3 y 3 3xy = 1 By using total differentiation concept, \(du = \left( {\frac{{\partial u}}{{\partial x}}} \right)dx \left( {\frac{{\partial u
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{(x,y) x y ≥ 1}, which is the region above the line y = 1 − x See figure above, right To compute the probability, we double integrate the joint density over this subset of the support set P(X Y ≥ 1) = Z 1 0 Z 2 1−x (x2 xy 3)dydx = 65 72 (c) We compute the marginal pdfs fX(x) = Z ∞ −∞ f(x,y)dy = ˆR 2 0 (x 2 xy 3)dyFirst type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More ExamplesWe are told to find the global extrema of the function f(x,y)=x^3y^33xy on the rectangle R=0,2\times{2},2 This R is a stratified set, having an open interior, the relative interiors More Items Share Copy Copied to clipboard Examples Quadratic equation { x } ^ { 2 } 4 x 5 = 0
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(a) x 2 y 2 2xy (b) x 2 y 2 – xy (c) xy 2 (d) 3xy polynomials In this question formula a 3 b 3 c 3 3abc = (abc)(a 2 b 2 c 2 abbcca) is used LHS part (xy) 3 (yz) 3 (zx) 3 3(xy)(yz)(zx) =(xy yz zxFind dy/dx x^33xyy^3=3 Differentiate both sides of the equation Differentiate the left side of the equation Tap for more steps Differentiate Tap for more steps By the Sum Rule, the derivative of with respect to is Differentiate using the Power Rule which states that is where
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3x4y=8 Geometric figure Straight Line Slope = 1500/00 = 0750 xintercept = 8/3 = yintercept = 8/4 = 2/1 = 0000 Rearrange Rearrange the equation by subtracting回答 您好，亲， (xy)的三次方可以用立方和公式求解： (xy)^3=x^33x^2y3xy^2y^3。 除此之外， (xy)^3= (xy)^2* (xy)= (x^22xyy^2)* (xy)=x^3x^2y2x^2y2xy^2xy^2y^3=x^33x^2y3xy^2y^3 亲，这两个公式都是可以直接用的，您可以把它记录在您的笔记本上面 更多1条 3X y is a binomial in which x and y are two terms In mathematics, the cube of sum of two terms is expressed as the cube of binomial x y It is read as x plus y whole cube It is mainly used in mathematics as a formula for expanding cube of sum of any two terms in their terms ( x y) 3 = x 3 y 3 3 x 2 y 3 x y 2
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x 3 3xyy 31=(x 3 3x 2 y3xy 2 y 31)3x 2 y3xy 2 3xy = (xy) 313xy(xy1) =(xy1)(x 2 2xyy 2 xy13xy) =(xy1)(x 2xyy 2 xy1) bởi Ngô hoàng anh anh Like (0) Báo cáo sai phạm Cách tíchThis answer is useful 5 This answer is not useful Show activity on this post Let ω be a complex cube root of unity Then x 3 − y 3 = ( x − y) ( x − ω y) ( x − ω 2 y) since both sides vanish when x ∈ { y, ω y, ω 2 y } and the degrees are right Since 1 ω ω 2 = 0 we have ω ω 2 = − 1Updated 4 years ago Author has 59K answers and M answer views (1) xy=1 (Given) Taking cubes of both sides, (xy)^3=1^3 Or, x^3 y^3 3xy (xy)=1 Substituting for xy = 1 from eq (1) on the LHS, we get the answer x^3 y^3 3xy =1
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Answer (1 of 3) x^3 y^3 = 3 x y \text{differentiating both sides with respect to x} 3 x^2 (3 y^2) \dfrac{\mathrm dy}{\mathrm dx} = 3 y (3 x) \dfrac{\mathrm dy For the curve defined by the equation \\L x^3\\,y^3\\,=\\,3xy, find an equation of the tangent at the point \\L ( \\frac{4}{3}\\, ,\\, \\frac{2}{3} ) I do \\L D(xOne Time Payment $1999 USD for 3 months Weekly Subscription $249 USD per week until cancelled Monthly Subscription $799 USD per month until cancelled Holidays Promotion Annual Subscription $1999 USD for 12 months (40% off) Then, $3499 USD per year until cancelled
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Click here👆to get an answer to your question ️ What should be added to x^3 3x^2y 3xy^2 y^3 to get x^3 y^3 Join / Login >> Class 8 >> Maths >> Algebraic Expressions and Identities >> Operations on Algebraic Expressions >> What should be added to x^3 Question What should be added to x 3 3 x 2 y 3 x y 2 y 3 to get x 3 y 3F(x,y)=x^3y^33xy 分别对x,y求偏导 fx=3x^23y fy=3y^23x 令fx=0,fy=0,可得x=0,y=0,或x=1,y=1这2个驻点 然后求二阶偏导 fxx=6x,fxy=3,fyy=6y x=0,y=0时,fxx=0,fxy=3,fyy=0,(3)^>0,所以(0,0)不是极值点;Ejercicios EDO's de primer orden 3 1 y3 dy = dx x2 Z y−3 dy = Z x−2 dx, 1 −2 y−2 = −x−1 c 1, −1 2y2 −1 x c 1, 1 y2 2 x c, c = −2c 1 Solución implícita 1 y2 2xc x Solución explícita y = ±
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